If the ratio of specific heat of a gas of constant pressure to that at constant volume is `gamma`, the change in internal energy of the mass of gas, when the volume changes from `V` to `2V` at constant pressure `p` is

Options

A. `R//(gamma-1)`
B. pV
C. `pV //(gamma-1)`
D. `gamma pV //(gamma-1)`

Answer

C

Explanation

`Delta U=n C_V Delta T=n((R)/(gamma-1))Delta T`
`implies Delta U=(P Delta V)/((gamma-1))=(P(2V-V))/(gamma-1)=(PV)/((gamma-1))`