In changing the state of thermodynamics ...

In changing the state of thermodynamics from A to B state, the heat required is Q and the work done by the system is W. The change in its internal energy is

A

Q + W

B

Q-W

C

Q

D

`(Q-W)/(2)`

Verified by Experts

The correct Answer is:

B

As `Delta Q=Delta U+Delta W implies Delta U=Q-W`.

Similar Questions

Explore conceptually related problems

If 150 J of heat is added to a system and the work done by the system is 110 j. then change in internal energy wil be

If heat given to a system is 6 kcal and work done is 6 k J . Then change in internal energy is

Heat given to a system is 30 joules and work done by the system is 15 joules. The change in the internal energy of the system will be

Heat given to a system is 35 joules and work done by the system is 15 joules. The change in the internal energy of the system will be

For a gaseous system, if heat rejected by the system is 100 J and work done by the system is 20 J , then change in internal energy is

A system is provided 50J of heat and work done on the system is 10Joule What is the change in internal energy

If the amount of heat given to a system is 40 J and the amount of work done on the system is 15 J then the change in internal energy is

For a gaseous state if heat supplied to the system is 100 J and work done by the system is 25 J. then internal energy of the system is

A system is provided 50 J of heat and work can be done on the system is 10 J. The change in internal energy during the process is: