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Iflambda=2.5 and volume is equal to (1)/...

If`lambda=2.5` and volume is equal to `(1)/(8)` times to the initial volume then perssure p' is equal to (initial pressure = p)

A

P' = P

B

P' = 2P

C

`P'= P xx (2)^(15//2)`

D

P = 7P

Text Solution

Verified by Experts

The correct Answer is:
C
Since, `PV^(gamma-1)` = constant
`(P_2)/(P_1)=((V_1)/(V_2))^(gamma) implies (P.)/(P)=(8)^(5//2)`
`implies P. = Pxx(2)^(15//2)`
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