In changing the state of a gas adiabatically from an equilibrium state A to another equilibrium state B an amount of work equal to 22.3 J is done on the system.If the gas is taken from state A to B via a process in which the net heat absorbed by the system is 9.35 cal then the net work done by the system in latter case is
(Take 1 case =4.2 J)

Options

A. 5.9J
B. 16.9 J
C. 9.3J
D. 4.6 J

Answer

B

Explanation

`Delta W= - 22.3J` (Since the work is done on the system)
`Delta Q=0`
Since, `DeltaQ=DeltaU + DeltaW implies Delta U= -(-22.3)=22.3J`
When the gas goes from state A to state B via a process, the net heat absorbed by the system is
`DeltaQ=DeltaU + DeltaW`
`implies DeltaW=(9.35) xx4.18-22.3=16.88 ~~ = 16.9J`