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In a Carnot engine when T(2) = 0^(@)C an...

In a Carnot engine when `T_(2) = 0^(@)C` and `T_(1) = 200^(@)C` its efficiency is `eta_(1)` and when `T_(1) = 0^(@)C` and `T_(2) = -200^(@)C`. Its efficiency is `eta_(2)`, then what is `eta_(1)//eta_(2)`?

A

0.577

B

0.733

C

0.638

D

Can not be calculated

Text Solution

Verified by Experts

The correct Answer is:
A
`eta_1=1-(273)(473)` and `eta_2=1-(73)/(273)`
`eta_1=(200)/(273)` and `eta_2=(200)/(273)`
`:. (eta_1)/(eta_2)=(273)/(473)=0.577`
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