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A reversible engine converts one-sixth o...

A reversible engine converts one-sixth of the heat input into work. When the temperature of the sink is reduced by `62^@C` , the efficiency of the engine is doubled. The temperatures of the source and sink are

A

`80^@C, 37^@C`

B

`95^@C, 28^@C`

C

`90^@C, 37^@C`

D

`99^@C, 37^@C`

Text Solution

Verified by Experts

The correct Answer is:
D
Initially `eta=(1-(T_2)/(T_1))=W/Q=1/6`
Finally, `eta. = (1-(T_2.)/(T_1))=(1-((T_2-62))/(T_(1)))`
`=eta+(62)/(T_(1)`
Since, `eta. = 2eta`
By solving-
`T_1=372 K=99^@C, T_2=310K = 37^@C`.
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