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The volume of one mole of ideal gas with...

The volume of one mole of ideal gas with adiabatic exponent is varied according to law `V = 1/T`. Find amount of heat obtained by gas in this process if gas temperature is increased by 100 K.

Text Solution

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The correct Answer is:
200
`C_V=R/(gamma-1)=R/(4/3-1)=3R`
As `Q=nC_V DeltaT and V = 1/T` (from question)
`:. PV =RT :. P =R/V^2`
`dQ = dU + PdV = C_vdT + PdV = R(gamma-1)dt-RdT`
`=(3R)/(4-3)xx100 – Rxx100 = 200R`
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