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An ideal engine whose low-temperature re...

An ideal engine whose low-temperature reservoir is at `27^@C` has an efficiency of 40%. By how much should the temperature of the high-temperature reservoir be increased so as to increase the efficiency to 50% ?

Text Solution

Verified by Experts

The correct Answer is:
100
`eta=1-T_L/T_H`
`:.40/100=1-((27+273))/(T_(H))implies 300/(T_H)=1-40/100 =0.6`
`:. T_(H) = 300/(0.6) = 500 K`
and `:. 50/100 =1 - 300/(T._H)`
`implies 300/(T._H)=1-50/100=0.5`
`:.T._H=300/(0.5)=600 K`
`:. (T._H-T_H) =600 -500 = 100 K`
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