Home
Class 11
PHYSICS
In a cold storage, ice melts at the rate...

In a cold storage, ice melts at the rate of `2 kg//h` when the external temperature is `20^(@)C`. Find the minimum power output of the motor used to drive the refrigerator which just prevents the ice from melting. Latent heat of fusion of `ice = 80 cal//g`

Text Solution

Verified by Experts

The correct Answer is:
`13.67`

Mass of ice that melts per second `=(2xx1000)/3600 =5/9g`
To prevent melting of ice, heat needed to be drawn out per second, `Q_2 =mL =5/9 xx80 =400/9` cal
Also ` T_2 = 273K, T_1 = 20 + 273 = 293 K`
Coefficient of performance, `beta = Q_2/W = T_2/(T_1-T_2)`
`:. W = (Q_2(T_1-T_2))/T_2=(400 xx(293 -273))/(9 xx 273)`
`=(400xx20)/(9xx273)"cal s"^(-1)= (8000 xx 4.2)/(9 xx 273)Js^(-1)`
`:.` Minimum power output of the motor used = 13.67 W.
Promotional Banner

Similar Questions

Explore conceptually related problems

How many calories of heat will be absorbed when 2kg of ice at 0^(@)C melts ? ( Specific latent heat of fusion of ice = 80 cal //g )

Calculate the amount of heat required to convert 80g of ice at 0^(@)C into water at the same temperature . ( Specific latent heat of fusion of ice = 80 cal //g )

Calculate the amount of heat required to convert5g of ice of 0^(@)C into water at 0^(@)C . ( Specific latent heat of fusion of ice 80 cal //g )

The entropy change in melting 1g of ice at 0^@C . (Latent heat of ice is 80 cal g^(-1) )

Find the heat required to convert 20 g of iceat 0^(@)C into water at the same temperature. ( Specific latent heat of fusion of ice =80 cal//g )

Calculate the amount of heat energy to be supplied to convert 2 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Calculate the amount of heat energy to be supplied to convert 4 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

A colorimeter contains 400 g of water at a temperature of 5^(@)C . Then, 200 g of water at a temperature of +10^(@)C and 400 g of ice at a temperature of -60^(@)C are added. What is the final temperature of the contents of calorimeter? Specific heat capacity of water -1000 cal //kg//K Specific latent heat of fusion of ice =80xx1000 cal //kg Relative specific heat of ice =0.5