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A perfect gas goes from state A to anoth...

A perfect gas goes from state A to another state B by absorbing 8 x `10^5` J of heat and doing 6.5 x `10^5` J of external work. It is now transferred between the same two states in another process in which it absorbs `10^5` J of heat. Then in the second process,

A

Work done on the gas is `0.5 xx10^5` J

B

Work done by gas is `0.5xx10^5J`

C

Work done on gas is `10^5J`

D

Work done by gas is `10^5J`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaQ = DeltaU+DeltaW`
`implies 8xx10^5 = DeltaU +6.5xx10^5`
`impliesDeltaU = 1.5xx10^5` J
Since final and initial states are same `DeltaU =` constant
For second process `- DeltaQ = DeltaU +DeltaW`
` implies 10^5 = 1.5xx10^5 + DeltaW implies DeltaW=-0.5 xx10^5 J`
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