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The work of 146 kJ is performed in order...

The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by `7^@C`. The gas is `(R=8.3ml^-1Jmol^-1K^-1)`

A

Triatomic

B

A mixture of monoatomic and diatomic

C

Monoatomic

D

Diatomic

Text Solution

Verified by Experts

The correct Answer is:
D
As `DeltaQ = 0, DeltaU=DeltaW`
Now, `nC_VDeltaT = DeltaW = 146xx10^3`
`=10^3xx(8.31)/(gamma-1)xx7 =146 xx10^3 ` [as `C_V=R/(gamma-1)` ]
`implies gamma = 1.4` i.e. gas is diatomic.
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