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A Carnot engine, whose efficiency is 40%...

A Carnot engine, whose efficiency is `40%`, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency `60%`. Then, the intake temperature for the same exhaust (sink) temperature must be:

A

Efficiency of carnot engine cannot be made larger than 50%

B

1200 K

C

750 K

D

600 K

Text Solution

Verified by Experts

The correct Answer is:
C
`eta =1 -(T_2)/(T_1) implies 0.4 = 1 -(T_2)/(T_1)`
`implies T_(2)/(T_1) =0.6 implies T_2 = 500 xx 0.6 = 300 K`
Now, `eta = 60 =1-300/(T_1)`
`implies 300/(T_1) = 0.4 ` or `implies T_1 = 750 K`
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