Home
Class 11
PHYSICS
A reversible engine has an efficiency of...

A reversible engine has an efficiency of `1/4` If the temperature of the sink is reduced by `58^(@)` C, its efficiency becomes double. Calculate the temperature of the sink :

A

`180.4^@C`

B

`382^@C`

C

`174^@C`

D

`280^@C`

Text Solution

Verified by Experts

The correct Answer is:
C

`T_2` sink temperature
`eta = 1-T_2/T_1`
`1/4=1-T_2/T_1`
`T_2/T_1=3/4`
`1/2=1-(T_2-58)/T_1`
`T_2/T_1-58/T_1=1/2`
`3/4 =58/T_1+1/2`
`1/4=58/T_1impliesT_1=232`
`T_2=3/4xx232`
`T_2=174^@C`
Promotional Banner

Similar Questions

Explore conceptually related problems

An engine has an efficiency of 0.25 when temperature of sink is reduced by 58^(@)C , If its efficency is doubled, then the temperature of the source is

An engine has an efficiency of 1/6 . When the temperature of sink is reduced by 62^(@)C , its efficiency is doubled. Temperature of the source is

The efficiency of carnot engine is 1/4. If the temperature of sink reduces by 58 degrees celsuis the efficiency doubles. Calculate temperature of sink.

A cannot engine has efficiency (1)/(6) . If temperature of sink is decreased by 62^(@)C then its efficiency becomes (1)/(3) then the temperature of source and sink:

The efficiency of heat engine is 1/6 when the temperature of sink is reduced by 62^0 C the efficiency doubles. What is the temperature of source?

A Carnot engine efficiency is equal to 1/7 . If the temperature of the sink is reduced by 65 K , the efficiency becomes 1/4 . The temperature of the source and the sink in the first case are respectively