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The equation describing the motion of a ...

The equation describing the motion of a simple harmonic oscillator along the X axis is given as `x = A cos (omega t + phi)`. If at time t = 0, the oscillator is at x = 0 and moving in the negative x direction, then the phase angle `phi` is

A

`pi//2`

B

`-pi//2`

C

`pi`

D

0

Text Solution

Verified by Experts

The correct Answer is:
A
`x=Acos(omegat+phi)`
`implies 0=Acosphi implies cosphi=0implies phi=pi//2`.
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