Home
Class 11
PHYSICS
The displacement of a particle executing...

The displacement of a particle executing simple harmonic motion is given by
`y=A_(0)+Asinomegat+Bcosomegat`
Then the amplitude of its oscillation is given by :

A

`A+B`

B

`A_(0)+sqrt(A^(2)+B^(2))`

C

`sqrt(A^(2)+B^(2))`

D

`sqrt(A_(0)^(2)+(A+B)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`y=A_(0)+Asinomegat+Bcosomegat`
Hence, 2 SHM.s are super imposed with phase difference of `pi/2`
Amplitude `=sqrt(A^(2)+B^(2)+2ABcosDeltaphi)" "[because Deltaphi=(pi)/(2)]`
`=sqrt(A^(2)+B^(2))`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by

The total energy of a particle executing simple harmonic motion is

The velocity of a particle executing simple harmonic motion is

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

While a particle executes linear simple harmonic motion

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The plot of velocity (v) versus displacement (x) of a particle executing simple harmonic motion is shown in figure. The time period of oscillation of particle is :-

The displacement of a particle executing simple harmonic motion is given by x=3sin(2pit+(pi)/(4)) where x is in metres and t is in seconds. The amplitude and maximum speed of the particle is

If a particle is executing simple harmonic motion, then acceleration of particle