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A 0.10 kg block oscillates back and fort...

A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: `x = (10 cm) cos [ (10 rads)t + pi//2 rad]` what is the maximum acceleration experiences by the block

A

`10m//s^(2)`

B

`10pim//s^(2)`

C

`(10pi)/(2)m//s^(2)`

D

`(10pi)/(3)m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`a_(max)=Aomega^(2)=((10)/(100))(10^(2))=10m//s^(2)`
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