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When the potential energy of a particle ...

When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is

A

A/4

B

A/3

C

A/2

D

2A/3

Text Solution

Verified by Experts

The correct Answer is:
C
`(PE)/((PE)_(Max))=((1)/(2)momega^(2)y^(2))/((1)/(2)momega^(2)A^(2))implies (1)/(4)=(y^(2))/(A^(2))`
`implies y=(A)/(2)`.
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