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When a mass M is attached to the spring ...

When a mass M is attached to the spring of force constant k , then the spring stretches by l . If the mass oscillates with amplitude l , what will be maximum potential energy stored in the spring

A

`(kl)/(2)`

B

`2kl`

C

`(1)/(2)Mgl`

D

`Mgl`

Text Solution

Verified by Experts

The correct Answer is:
B
Since, `Mg=kl`
`(PE)_(max)=(1)/(2)k(2l)^(2)=2kl` (as `A=2l`).
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