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The amgular velocity and the amplitude o...

The amgular velocity and the amplitude of a simple pendulum is `omega` and a respectively. At a displacement x from the mean position, if its kinetic energy is T and potential energy is U, then the ratio of T to U is

A

`X^(2)omega^(2)//(a^(2)-X^(2)omega^(2))`

B

`X^(2)//(a^(2)-X^(2))`

C

`(a^(2)-X^(2)omega^(2))//X^(2)omega^(2)`

D

`(a^(2)-X^(2))//X^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(KE)/(PE)=((1)/(2)momega^(2)(A^(2)-x^(2)))/((1)/(2)momega^(2)x^(2))`
`implies (T)/(V)=(A^(2)-X^(2))/(X^(2))=(a^(2)-X^(2))/(X^(2))`.
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