Home
Class 11
PHYSICS
The ration of kinetic energy to the pote...

The ration of kinetic energy to the potential energy of a particle executing SHM at a distance equal to half its amplitude , the distance being measured from its equilibrium position is

A

`4:1`

B

`8:1`

C

`3:1`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`(KE)/(PE)=((1)/(2)momega^(2)(A^(2)-y^(2)))/((1)/(2)momega^(2)y^(2))=(A^(2)-((A)/(2))^(2))/(((A)/(2))^(2))=(3A^(2))/(4)xx(4)/(A^(2))`
`=3:1`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The kinetic energy and the potential energy of a particle executing SHM are equal The ratio of its displacement and amplitude will be

The ratio of the kinetic to potential energy of a particle in SHM, when its displacement is one-half the amplitude, is

The P.E. of a particle executing SHM at a distance x from its equilibrium position is

The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal, when displacement (amplitude =a ) is

The potential energy of a particle executing S H M is 25 J. when its displacement is half of amplitude. The total energy of the particle is

Ratio of kinetic energy to potential energy of an oscillator when it is at distance 1//N times of amplitude from mean positions in

What is the ratio betweenthe potential energy and the total energy of a particel executing SHM, when its diplacement is half of its amplitude?

The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is 5 cm//s^(2) . Its acceleration at a distance of 2 cm from equilibrium position is

The potential energy of a particle execuring S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle be

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be