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A solid cylinder of mass 3 kg is rolling...

A solid cylinder of mass `3 kg` is rolling on a horizontal surface with velocity `4 ms^(-1)`. It collides with a horizontal spring of force constant `200 Nm^(-1)`. The maximum compression produced in the spring will be `:`

A

`0.5 m`

B

`0.6`m

C

`0.7m`

D

`0.2m`

Text Solution

Verified by Experts

The correct Answer is:
B
According to law of conservation of energy-Loss in KE of cylinder=Gain in PE of spring
`implies (1)/(2)mv^(2)=(1)/(2) Iomega^(2)=(1)/(2) kx^(2)`
`=(1)/(2)mv^(2)=(1)/(2)(mR^(2))/(2)((v)/(R))^(2)=(1)/(2)kx^(2)`
`implies (3)/(4)mv^(2)=(1)/(2)kx^(2)`
`implies (3)/(4)xx3xx(4)^(2)=(1)/(2)xx200xx x^(2)`
`x=0.6`m.
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