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The variation of potential enegy of harm...

The variation of potential enegy of harmonic oscillator is as shown in figure. The spring constant is

A

`1xx10^(2)N//m`

B

`150N//m`

C

`0.667xx10^(2)N//m`

D

`3xx10^(2)N//m`

Text Solution

Verified by Experts

The correct Answer is:
B
`(PE)_("Total")=0.04J`
Resting PE=0.01 J
Maximum KE=0.04-0.01=0.03 J
`implies 0.03=(1)/(2)momega^(2)A^(2)=(1)/(2)kA^(2)`
`0.03=(1)/(2)xxk((20)/(1000))^(2) implies k=150N//m`.
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