Home
Class 11
PHYSICS
The amplitude of a particle executing SH...

The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be

A

`E/2`

B

`(3)/(4)E`

C

`(9)/(16)E`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C

`E=(1)/(2) momega^(2)A^(2)`
As T=constant
`E prop A^(2) implies (E.)/(E)=(A^(.2))/(A^(2))implies E.=(E((3)/(4)A)^(2))/(A^(2))implies E.=(9E)/(16)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

When the amplitude of a particle executing S.H.M. is increased slightly its period

The total energy of a particle executing S.H.M. is proportional to

When the displacement of a particle executing SHM is one-fourth of its amplitude, what fraction of the total energy is the kinetic energy?

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle executing SHM has a total energy E. Another particle of twice the mass of the first particle executes SHM with 4 times the frequency and twice the amplitude of the first. Its total energy is

When displacement of a particle executing SHM is half of the amplitude,its potential energy is 5 J. Find the total energy of the particle in SHM,if potential energy at mean position is zero.

The total energy of a vibrating particle in SHM is E . If its amplitude and time period are doubled, its total energy will be :-