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A simple pendulum is executing simple ha...

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of is

A

0.1

B

0.21

C

0.3

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
A
`T=2pisqrt((l)/(g)) implies (T_(1))/(T_(2))=sqrt((l_(1))/(l_(2)))`
`implies (T_(1))/(T_(2))=sqrt((100)/(121)) implies T_(2)=1.1 T_(1)`
% increase`=(T_(2)-T_(1))/(T_(1)) xx100=10%`.
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