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A particle executes simple harmonic moti...

A particle executes simple harmonic motion between `x=-A and x=+A`. The time taken for it to go from 0 to A/2. is `T_(1)` and to go from A/2 to A is `T_(2)`. Then:

A

`T_(1) lt T_(2)`

B

`T_(1) gt T_(2)`

C

`T_(1)=T_(2)`

D

`T_(1)=2T_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`x=Asinomegat`
for `x=A//2," "(A)/(2)=AsinomegaT_(1) implies T_(1)=(pi)/(6omega)`
for `x=A," "Asinomega(T_(1)+T_(2))=A implies T_(1)+T_(2)=(pi)/(2omega)`
`T_(2)=(pi)/(2omega)-T_(1)=(pi)/(3omega)` i.e., `T_(2) gt T_(1)`.
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