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Two blocks each of mass m are connected ...

Two blocks each of mass m are connected to a spring of spring constant k. if both are given velocity v in opposite directions, then the maximum elongation of the spring is

A

`sqrt((mv^(2))/(k))`

B

`sqrt((2mv^(2))/(k))`

C

`sqrt((mv^(2))/(2k))`

D

`2sqrt((mv^(2))/(k))`

Text Solution

Verified by Experts

The correct Answer is:
B
Law of conservation of energy-
`(1)/(2) mv^(2)+(1)/(2)mv^(2)=(1)/(2)kx^(2)`
`implies mv^(2)=(1)/(2) kx^(2) implies x=sqrt((2mv^(2))/(k))`.
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