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A mass of 4 kg suspended from a spring o...

A mass of 4 kg suspended from a spring of spring constant `800 Nm^(-1)` executes simple harmonic oscillations. If the total energy of the oscillator is 4 J, the maximum acceleration (in `ms^(-2)`) of the mass is

A

5

B

15

C

45

D

20

Text Solution

Verified by Experts

The correct Answer is:
D
Since. Total energy-
`E=(1)/(2)kA^(2)`
`implies A^(2)=(4xx2)/(800)=(1)/(100) implies A=0.1m`
maximum acceleration-
`a_(max)=omega^(2)A=(k)/(m)`A
`implies a_(max)=(800)/(4)xx0.01=20m//s^(2)`
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