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A sphere is hung with a wire 30^(@) rota...

A sphere is hung with a wire `30^(@)` rotation of the sphere about the wire generates a restoring torque of 4.6 Nm. If the moment of inertia of the sphere is 0.082 kg `m^2`, deduce the frequency of angular oscillations.

Text Solution

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The correct Answer is:
`1.65`

Here `theta = 30^(@) = (pi)/(6) "rad", tau = 4.6 Nm `
`I = 0.082 kg m^(2)`
Restoring torque per unit angular displacement
`C = (tau)/(theta) = ( 4.6)/(pi//6)`
`= (4 . 6 xx 6 xx 7)/(22) = 8.78 Nm rad^(-1)`
`:.` Frequency ` v = (1)/(2pi) sqrt((C)/(I))`
`= (7)/( 2 xx 22) sqrt((8.78)/(0.082)) = 1.65 Hz`
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