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A particle executing simple harmonic mot...

A particle executing simple harmonic motion of amplitude `5cm` has maximum speed of `31.4 cm//s` The frequency of its oscillation is

A

3 Hz

B

2 Hz

C

4 Hz

D

1 Hz

Text Solution

Verified by Experts

The correct Answer is:
D
`A = 5 cm, v_("max") = 31.4 cm//s `
`v_(m) = Aomega `
`rArr 31.4 = 5 xx 2 pi f`
`rArr f = (31.4)/(10 pi) = 1 Hz`
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