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A particle is executing simple harmonic ...

A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :

A

`(A)/(2 sqrt(2))`

B

`(A)/(2)`

C

A

D

`(A)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
K.E. = P.E
`(1)/(2) K (A^(2) - x^(2)) = (1)/(2) kx^(2)`
`A^(2) - x^(2) = x^(2) rArr x = pm (A)/(sqrt(2))`
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