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A silver atom in a solid oscillates in s...

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of `10^(12)//sec`. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver = 108 and Avagadro number `=6.02xx10^(23)" gm "mole^(-1))

A

2.2 N/m

B

5.5 N/m

C

6.4 N/m

D

7.1 N/m

Text Solution

Verified by Experts

The correct Answer is:
D
Frequency (f) `= 10^(12) Hz`
`omega = 2 pi xx 10 ^(12) ` rad/sec
`omega = sqrt((k)/(m)) rArr k = m omega ^(2)`
`rArr (( 108)/( 6.023 xx 10^(23))) xx 10^(-3) xx (2 pi xx 10 ^(12))^(2)`
`rArr k = 7.1N//n`
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