Home
Class 11
PHYSICS
The wave described by y = 0.25 sin ( 10 ...

The wave described by y `= 0.25 sin ( 10 pix -2pi nt )` where x and y are in meters and t in seconds , is a wave travelling along the

A

Positive x direction with frequency 1 Hz and wavelength `lambda=0.2m`

B

Negative x direction with amplitude 0.25 m and wavelength `lambda=0.2m`

C

Negative x direction with frequency 1 Hz

D

Positive x direction with frequency `pi` Hz and wavelength `lambda=0.2m`

Text Solution

Verified by Experts

The correct Answer is:
A
`y=0.25sin(10pix-2pit)`
`lambda=(2pi)/(k)=(2pi)/(10pi)=0.2m`
`f=(omega)/(2pi)=(2pi)/(2pi)=1Hz`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The wave described by y = 0.25 "sin"(10 pi x - 2pit) , where x and y are in metres and t in seconds , is a wave travelling along the:

The wave decribed by y=0.25sin(10pix-2pit) . Where x and y are in metre and t is second, is a wave travelling along the Therefore, the wave is travelling along +ve x direction with frequency 1 Hz and wavelength 0.2m

The equation of a wave is given by y=a sin (100t-x/10) where x and y are in metre an t in second, the velocity of wave is

A wave travels in a medium according to the equation of displacement given by y(x, t)=0.03 sin pi (2 t-0.01 x) where y and x are in metres and t in seconds. The wavelength of the wave is

The equation of a simple harmonic wave is given by y = 3 sin"(pi)/(2) (50t - x) where x and y are in meters and x is in second .The ratio of maximum particle velocity to the wave velocity is