Home
Class 11
PHYSICS
When a wave travels in a medium, the par...

When a wave travels in a medium, the particle displacement is given by the equation
`y=asin 2pi(bt-cx), ` where `a,b` and `c` are constants. The maximum particle velocity will be twice the wave velocity. If

A

`c=(1)/(pia)`

B

`c=pia`

C

`b=ac`

D

`b=(1)/(ac)`

Text Solution

Verified by Experts

The correct Answer is:
A
`y=asin2pi(bt-cx)`
`(v_(p))_(max)=aomega=a(2pib)`
`k=(2pi)/(lambda)=2pic` [where `c=(1)/(lambda)`]
`v=(omega)/(k)=(2pib)/(2pic)=(b)/(c)`
Given, `(v_(p))_(max)=2v`
`implies 2piab=2xx(b)/(c)impliesc=(1)/(pia)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

When a wave travels in a medium, th eparticle displacement is given by the equation y=asin 2pi(bt-cx), where a,b and c are constants. The maximum particle velocity will be twice the wave velocity. If

When a wave travels in a medium, the particle displacement is given by, y = psin2 pi (qt - rx), where p, q and r are constants. The maximum particle velocity will be twice the wave velocity if

When a wave travels from one medium to another, the displacement of the particle is given as y = a sin 2pi (mt - nx) m and n are constants.

Transverse wave is described by the equation y=y_0 sin 2pi (ft-x/lambda) .The maximum particle velocity is twice the wave velocity if wavelength is____

A transverse wave is described by the equation y=A sin 2pi( nt- x//lambda_0) . The maximum particle velocity is equal to 3 times the wave velocity if

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A travelling wave is described by the equation y = y_(0) sin ((ft - (x)/lambda)) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-

A traverse wave is repersented by the equation y=y_(0)sin(2pi)/(lambda)(vt-x) For what value of lambda the maximumn particle velocity equal to two times the wave velocity

A transverse wave is described by the equation y=A sin [2pi(ft-x//lambda)] . The maximum particle velocity is equal the wave velocity if :