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The phase difference between two wa...

The phase difference between two waves represented by `y_(1)=10 ^(-6) sin [100 t+(x//50)+0.5]m, y_(2)=10^(-6) cos[100t+(x//50)]m`where x is expressed in metres and t is expressed in seconds, is approximately

A

1.5 rad

B

1.07 rad

C

2.07 rad

D

0.5 rad

Text Solution

Verified by Experts

The correct Answer is:
B
`y_(1)=10^(-6)sin[100t+(x)/(50)+0.5]`
`y_(2)=10^(-6)sin[100t+(x)/(50)+(pi)/(2)]`
`Deltaphi=[100t+(x)/(50)+1.57]-[100t+(x)/(50)+0.5]`
`=1.07rad//sec`.
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