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A wire of density 9 xx 10^(3) kg//m^(3) ...

A wire of density `9 xx 10^(3) kg//m^(3)` is stretched between two clamps 1 m apart and is subjected to an extension of `4.9 xx 10^(-4) m`. The lowest frequency of transverse vibration in the wire is `(Y = 9 xx 10^(10) N//m^(2))`

A

40 Hz

B

35 Hz

C

30 Hz

D

25 Hz

Text Solution

Verified by Experts

The correct Answer is:
B
`f=|(1)/(2l)sqrt((T)/(mu))=(1)/(2l)sqrt((Y((Deltal)/(l))A)/(Arho))` [as `Y=(T//A)/(Deltal//l)` and `mu=Arho`]
`f=(1)/(2l)sqrt((YDeltal)/(lrho))`
`=(1)/(2xx1)sqrt((9xx10^(10)xx4.9xx10^(-4))/(1xx9xx10^(3)))=35Hz`.
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