Home
Class 11
PHYSICS
A pipe of length 85cm is closed from one...

A pipe of length `85cm` is closed from one end. Find the number of possible natural oscillations of air column in the pipe whose frequencies lie below `1250 Hz`. The velocity of sound in air is `34m//s`.

A

12

B

8

C

6

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
`f_("closed")=((2n-1)v)/(4l)`
`implies ((2n-1)v)/(4l)le1250implies((2n-1)xx340)/(4xx0.85)le1250`
`implies 2n-1=(1250xx4xx0.85)/(340)`
`implies nle6.025 implies n~~6` (nearest smallest integer).
Promotional Banner

Similar Questions

Explore conceptually related problems

A pipe of length 85 cm is closed one end. Find the number of possible natural oscillationsof air column in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.

A pipe closed at one end has length 83 cm. The number of possible natural oscilations of air column whose frequencies lie below 1000 Hz are (take, velocity of sound in air 332 m/s)

The number of possible natural oscillations of air column in a pipe closed at one end of length 85 cm whose frequencies lie below 1250 Hz are (velocity of sound =340ms^(-1) ).

Find the number of possible natural oscillations of air column in a pipe whose frequencies lie below f_(0) = 1250 Hz . The length of the pipe is l = 85 cm . The velocity of sound is v = 340 m//s . Consider two cases the pipe is closed from one end .

How many frequencies below 1 kH_(Z) of natural oscillations of air column will be produced if a pipe of length 1 m is closed at one end? [ velocity of sound in air is 340 m//s ]

Find the number of possible natural frequencies of an air column in a pipe whose frequencies lie below 1250 Hz. The length of the pipe is 85 cm. The speed of sound is 340 ms^(-1) . Consider the two cases: (a) the pipe is closed at one end and (b) the pipe is open at both ends.