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The frequency of a stretched uniform wir...

The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N , it is in resonance with the first overtone of the closed tube. The initial tension in the wire is

A

1 N

B

4 N

C

8 N

D

16 N

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(2l)sqrt((T)/(mu))=(v)/(4l)...(i)`
and `(1)/(2l)sqrt((T+8)/(mu))=(3v)/(4l)...(ii)`
from (i) and (ii)
`sqrt((T)/(T+8))=(1)/(3)impliesT=1N`.
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