Home
Class 11
PHYSICS
A source and an observer approach each o...

A source and an observer approach each other with same velocity 50 m/s . If the apparent frequency is `435 sec^( –1)`, then the real frequency is

A

`320sec^(-1)`

B

`360sec^(-1)`

C

`390sec^(-1)`

D

`420sec^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`f.=f((v+v_(o))/(v-v_(s)))implies435=f((332+50)/(332-50))`
`implies f=321.2sec^(-1)~~320sec^(-1)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A source and an observer approach each other with same velocity 50 m/s. If the apparent frequency is 434 Hz, then the real frequency is (Given velocity of sound = 332 m/s)

An observer and source are approaching one another with a relative velocity of 50 m/s. If the true frequency of the source is 1000 Hz, determine the observed frequency when (i) Observer is stationary (ii) Source is stationary

A source and an observer move away from each other with a velocity of 10 m/s with respect to ground. If the observer finds the frequency of sound coming from the source as 1950 Hz , then actual frequency of the source is (velocity of sound in air = 340 m/s )

A source of sound and listener are approaching each other with a speed of 40 m / s . The apparent frequency of note produced by the source is 400 cps . Then, its true frequency (in cps ) is (velocity of sound in air = 360 m / s )

If a source of sound of frequency upsilon and a listener approach each other with a velocity equal to (1//20) of velocity of sound, the apparent frequency heard by the listener is

A source of sound is moving away from an observer at rest with a velocity of 50 m s^(-1) . If the frequency of sound is 200 Hz , find the apparent frequency observed by the observer. (Take velocity of sound = 300 m s^(-1))

A sound source emitting sound of frequency 450 Hz is approaching a stationary observer with velocity 30 ms^(-1) and another identical source is going away from the observer with the same velocity. If the velocity of sound is 330 ms^(-1) , then the difference of frequencies heard by observer is

The speed of sound in air at a given temperature is 350 m/ s. An engine blows whistle at a frequency of 1200 cps. It is approaching the observer with velocity 50 m/s. The apparent frequency in cps heard by the observer will be

Two waves are approaching each other with a velocity of 16 m/s and frequency n. The distance between two consecutive nodes is