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The amplitude of sound is doubled and th...

The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be

A

Increased by a factor of 2

B

Decreased by a factor of 2

C

Decreased by a factor of 4

D

Unchanged

Text Solution

Verified by Experts

The correct Answer is:
C
Intensity `prop"(Amplitude)"^(2)"(frequency)"^(2) [because I=2pi^(2)a^(2)f^(2)vrho]`
`(I_(1))/(I_(2))=((a)/(2a))^(2)xx((f)/(f//4))^(2)impliesI_(2)=(I_(1))/(4)`.
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