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Charges 4Q, q and Q and placed along x-a...

Charges 4Q, q and Q and placed along x-axis at positions `x=0,x=1//2` and `x=1`, respectively. Find the value of q so that force on charge Q is zero

A

x = 0.775m

B

x = 1.2m

C

x = 0.5m

D

Position depends on the amount of charge

Text Solution

Verified by Experts

The correct Answer is:
A

`F_1 = F_2`
`implies (K xx6 xxqxx10^(-6))/x^2 = (Kxx15 xx10^(-6)xxq)/((2-x)^2)`
`implies (2-x)/x=sqrt(15/6)=1.58 implies 2 - x = 1.58x`
`implies x =2/(2.58) = 0.775m`
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