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When charge is given to a soap bubble, i...

When charge is given to a soap bubble, it shows:Two equal negative charges -q are fixed fixed at point (0, -a) and (0,a) on y-axis. A positive charge Q is released from rest at the point (2a, 0) on the x-axis. The charge Q will:

A

Execute simple harmonic motion about the origin

B

Move to the origin and remain at rest

C

Move to infinity

D

Execute oscillatory but not simple harmonic motion

Text Solution

Verified by Experts

The correct Answer is:
D

`F_("net") = 2Fcos theta`
`=2(1)/(4piepsilon_0)(-qQ)/((a^2+x^2))xx(x)/((a^2+x^2)^(1//2))`

`implies F_("net") =-1/(4piepsilon_0) .(2qQx)/((a^2+x^2)^(3//2))`
As `F_("net")` is not linear with x, motion will be oscillating but not SHM.
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