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ABC is an equilateral triangle. Charges ...

`ABC` is an equilateral triangle. Charges `+q` are placed at each corner. The electric intensity at `O` will be

A

`1/(4pi epsilon_0)q/r^2`

B

`1/(4pi epsilon_0)q/r`

C

Zero

D

`1/(4pi epsilon_0)((3q)/r^2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`vecF_(A) + vecF_(B) + vecF_(C) =0`
Because of equal angles.
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