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An electron is accelerated in an electri...

An electron is accelerated in an electric field of `40V cm^(-1)`. If `e//m` of electron is `1.76 xx10^(11) Ckg^(-1)` , then its acceleration is

A

`8.8 xx10^(14) m//sec^2`

B

`6.2 xx10^(13) m//sec^2`

C

`5.4 xx10^(12) m//sec^2`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
A
`ma = qEimplies a =(qE)/(m) = 1.76 xx10^(11) xx50 xx10^2`
`=8.8 xx10^(14)m//sec^2`
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