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A charged particle of mass 5 xx 10^(-5) ...

A charged particle of mass `5 xx 10^(-5) kg` is held stationary in space by placing it in an electric field of strength `10^(7) NC^(-1)` directed vertically downwards. The charge on the particle is

A

`-20 xx10^(-5) muC`

B

`-5 xx10^(-5) muC`

C

`5 xx10^(-5) muC`

D

`20 xx10^(-5) muC`

Text Solution

Verified by Experts

The correct Answer is:
B
`qE=(mg)implies q=(5xx10^(-5)xx10)/(10^7)`
`=5 xx10^(-11)C=5 xx10^(-5) muC`
Since, E is directed downward, hence q is -ve.
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