Home
Class 12
PHYSICS
A pendulum bob of mass 30.7 xx 10^(-6)kg...

A pendulum bob of mass `30.7 xx 10^(-6)kg` and carrying a chargee `2 xx 10^(-8)C` is at rest in a horizontal uniform electric field of `20000V//m`. The tension in the thread of the pendulum is `(g = 9.8 m//s^(2))`

A

`3 xx10^(-4) N`

B

`4 xx10^(-4) N`

C

`5 xx10^(-4) N`

D

`6 xx10^(-4) N`

Text Solution

Verified by Experts

The correct Answer is:
C

`T=sqrt((mg)^2+(qE)^2)`
`=sqrt((30.7xx10^(-6)xx9.8)^(2)+(2xx10^(-8)xx2 xx10^4)^2)`
`=sqrt(2.50 xx10^(-7))`
`~~5 xx10^(-4) N`
Promotional Banner

Similar Questions

Explore conceptually related problems

A pendulum bob of mass m = 80 mg, carrying a charge of q=2xx10^(-8)C , is at rest in a horizontal, uniform electric field of E = 20,000 V/m. The tension T in the thread of the pendulum and the angle alpha it makes with vertical, is (take g=9.8m//s^(2) )

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A pendulum bob of mass 80mg and carrying a charge of 2 times10^(-4) coulomb is at rest in a uniform horizontal electric field of 20kV/m .The tension in the thread of the pendulum is x times 10^(-4) N.Find value of x?

A pendulum bob of mass 80 mg and carrying charge of 3 xx 10 ^(-8) C is placed in an horizontal electric field. It comes to equilibrium position at an angle of 37^@ with the vertical. Calculate the intensity of electric field. (g = 10 m//s^2 )

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 2000V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

A pendulum bob of mass m charge q is at rest with its string making an angle theta with the vertical in a uniform horizontal electric field E. The tension in the string in

A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :

A Water of mass 3.2xx10^(-18)kg and carrying a charge of 1.6xx10^(-19)C is suspended stationary betwaeen two plates of an electric field. Given g=10 m//s^(2) , the intensity of the electric field required is

A charged ball of mass 8.4xx10^(16) kg is found to remain suspended in a uniform electric field of 2xx10^(4) Vm^(-1) . Calculate the charge on the ball. Given g = 10 m//s^(2)

A uniform electric field of 3xx10^4 N/C is applied iin a horizontal direction . A pendulum bob of mass 90 mg and carrying a charge of 1.5xx10^(-8) C is suspended through a string of length 1m. Calculate tension developed in the string and the angle made by the string with the vertical .