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A charge +q is placed at the origin O o...

A charge `+q` is placed at the origin O of X- Y axes as shown in the figure . The work done in taking a charge Q from A to B along the straight line AB is

A

`(qQ)/(4pi epsilon_0)((a-b)/(ab))`

B

`(qQ)/(4pi epsilon_0)((b-a)/(ab))`

C

`(qQ)/(4pi epsilon_0)(b/a^2-1/b)`

D

`(qQ)/(4pi epsilon_0)(a/b^2-1/b)`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=QV_(BA)=Q(V_B-V_A)`
`=Q[(Kq)/b-(Kq)/a]=(Qq)/(4piepsilon_0)[(a-b)/(ab)]`
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