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The displacement of a chrage Q in the el...

The displacement of a chrage `Q` in the electric field
`E = e_(1)hati + e_(2)hatj + e_(3)hatk " is " vecr = ahati + bhatj`. The work done is

A

`Q(ae_1+be_2)`

B

`Qsqrt((ae_1)^2(+be_2)^2)`

C

`Q(e_1+e_2)sqrt(a^2+b^2)`

D

`Q(sqrt(e_1^2+e_2^2))(a+b)`

Text Solution

Verified by Experts

The correct Answer is:
A
`W = vecF.vecS =qvecE.vecS`
`=Q(e_1hati+e_2hatj+e_3hatk).(ahati+bhatj)=Q(e_1a+e_2b)`
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