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Poistive and negative point charges of e...

Poistive and negative point charges of equal magnitude are kept at `(0, 0, a/2)` and `(0, 0, (-a)/(2))` respectively. The work done by the electric field when another poistive point charge is moved from `(-a, 0, 0)` to `(0, a, 0)` is

A

Positive

B

Negative

C

Zero

D

Depends on the path connecting the initial and final positions

Text Solution

Verified by Experts

The correct Answer is:
C

Point A(-a,0,0) on xaxis :
`V_A=0`
`V_A=0`
Because distance is same and sum of charges = 0
Point B (0, a,0) on y-axis :
`V_B =0`
Distance is same and sum of charges = 0.
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