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A ball of mass 1g and charge 10^(-8) C m...

A ball of mass `1g` and charge `10^(-8) C` moves from a point `A`. Where potential is `600` volt to the point `B` where potential is zero. Velocity of the ball at the point `B` is `20 cm//s`. The velocity of the ball at the point `A` will be

A

22.8 cm/s

B

228 cm/s

C

16.8 cm/s

D

168 m/s

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaK = qV`
`implies 1/2 m(v_f^2 -v_i^2) =qV`
`implies1/2 xx1 xx10^(-3)[(0.2)^2-v_i^2]=10^(-8) xx600`
`implies 0.04 -v_i^(2) = 0.012 implies v_i^2 = 0.028`
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