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The electric intensity due to a dipole o...

The electric intensity due to a dipole of length `10 cm` and having a charge of `500 muC`, at a point on the axis at a distance `20 cm` from one of the charges in air is

A

`6.25 xx10^(7) N//C`

B

`9.28 xx10^(7) N//C`

C

`13.1 xx10^(11) N//C`

D

`20.5 xx10^(7) N//C`

Text Solution

Verified by Experts

The correct Answer is:
A

`2a = 0.1 m, q = 500 muC , r = 0.25 cm`
Since, r is comparable of a
`E=(K(2p)r)/((r^2-a^2)^2)=(9xx10^9 xx2 xx(2aq) xx0.25)/([(0.25 )^2 -(0.05)^2]^2)`
`= (9xx10^9 xx2xx0.1 xx5 xx10^(-4)xx0.25)/([(0.25 )^2 - (0.05)^2]^(2))`
`= 6.25 xx10^7 N//C`
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